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Home » Solution: The vertex of a parabola $ h(x) = x^2 - 4x + c $ occurs at $ x = \frac-(-4)2(1) = 2 $, which matches the given condition. Now substitute $ x = 2 $ and set $ h(2) = 3 $: - AMAZONAWS

Solution: The vertex of a parabola $ h(x) = x^2 - 4x + c $ occurs at $ x = \frac-(-4)2(1) = 2 $, which matches the given condition. Now substitute $ x = 2 $ and set $ h(2) = 3 $: - AMAZONAWS

Finding the Vertex of the Parabola $ h(x) = x^2 - 4x + c $: A Step-by-Step Solution

📅 March 11, 2026 👤 scraface
Mar 11, 2026
Solution: The vertex of a parabola $ h(x) = x^2 - 4x + c $ occurs at $ x = \frac{-(-4)}{2(1)} = 2 $, which matches the given condition. Now substitute $ x = 2 $ and set $ h(2) = 3 $:

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