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Home » However, if we assume a typo and the result should be \(eginpmatrix 0 \ 0 \ k \endpmatrix\) with \(k = eginpmatrix 0 \ 0 \ \mathbfa \cdot \mathbfu \endpmatrix\), but none matches. - AMAZONAWS

However, if we assume a typo and the result should be \(eginpmatrix 0 \ 0 \ k \endpmatrix\) with \(k = eginpmatrix 0 \ 0 \ \mathbfa \cdot \mathbfu \endpmatrix\), but none matches. - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
However, if we assume a typo and the result should be \(egin{pmatrix} 0 \ 0 \ k \end{pmatrix}\) with \(k = egin{pmatrix} 0 \ 0 \ \mathbf{a} \cdot \mathbf{u} \end{pmatrix}\), but none matches.

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