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Home » This equation is in the standard form \(\frac(x-h)^2a^2 - \frac(y-k)^2b^2 = 1\), where \((h, k)\) is the center. Here, \(h = 0\) and \(k = 0\), so the center of the hyperbola is at the origin. - AMAZONAWS

This equation is in the standard form \(\frac(x-h)^2a^2 - \frac(y-k)^2b^2 = 1\), where \((h, k)\) is the center. Here, \(h = 0\) and \(k = 0\), so the center of the hyperbola is at the origin. - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
This equation is in the standard form \(\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1\), where \((h, k)\) is the center. Here, \(h = 0\) and \(k = 0\), so the center of the hyperbola is at the origin.

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