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s^2 = 144 \quad \Rightarrow \quad s = 12 - AMAZONAWS
s^2 = 144 \quad \Rightarrow \quad s = 12 - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 Now combine with \( \cos^2(\phi) = \frac{1}{2} \). The only solution satisfying both is \( \phi = -\frac{\pi}{4} \) (since \( \phi = \frac{\pi}{4} \) would give \( \cos^2 = \frac{1}{2} \), but \( \cos\left(\frac{\pi}{2} + \frac{\pi}{4}\right) = \cos\left(\frac{3\pi}{4}\right) = -\frac{1}{\sqrt{2}} \), not zero). However, satisfying \( \cos\left(\frac{\pi}{2} + \phi\right) = 0 \) implies:
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📌 Factor the quadratic: \( (n + 7)(n - 6) = 0 \).
