R'(t) = racddt(3t^3 - 5t^2 + 2t + 10) = 9t^2 - 10t + 2. - AMAZONAWS

Understanding R'(t) = d/dt(3t³ - 5t² + 2t + 10) | The Derivative Explained

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$R'(t) = rac{d}{dt}(3t^3 - 5t^2 + 2t + 10) = 9t^2 - 10t + 2.$