\mathbfc = \mathbfi((-3)(-2) - (1)(4)) - \mathbfj((2)(-2) - (1)(1)) + \mathbfk((2)(4) - (-3)(1)) - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$\mathbf{c} = \mathbf{i}((-3)(-2) - (1)(4)) - \mathbf{j}((2)(-2) - (1)(1)) + \mathbf{k}((2)(4) - (-3)(1))$