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Given \( A = 36\sqrt3 \), we solve for \( s \): - AMAZONAWS
Given \( A = 36\sqrt3 \), we solve for \( s \): - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 Solution: We are partitioning $6$ distinguishable objects (proposals) into $3$ non-empty, indistinct subsets (teams). This is given by the Stirling number of the second kind $S(6,3)$.
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