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\boxed{\frac{\sqrt5}5} - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
\boxed{\frac{\sqrt{5}}{5}}

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  • Thus, the area is:
  • $ \sin^2 rac{\pi}{2} = 1 $, $ \cos^2(2 \cdot rac{\pi}{2}) = \cos^2 \...
  • Thus, \( x = 0 \) or \( x = 2 \).
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