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Home » $AB = \sqrt(4-1)^2 + (5-2)^2 + (6-3)^2 = \sqrt9 + 9 + 9 = \sqrt27 = 3\sqrt3$ - AMAZONAWS

$AB = \sqrt(4-1)^2 + (5-2)^2 + (6-3)^2 = \sqrt9 + 9 + 9 = \sqrt27 = 3\sqrt3$ - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
$AB = \sqrt{(4-1)^2 + (5-2)^2 + (6-3)^2} = \sqrt{9 + 9 + 9} = \sqrt{27} = 3\sqrt{3}$

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