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📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 Thus, $ (x^2 + x + 1)^3 = 0 $ at $ x = \omega $, so $ x^2 + x + 1 $ is divisible by $ x^2 - x + 1 $, since both are degree 2 and the first vanishes where the second does.
