Wait — perhaps the oceanographer uses a cubic that fits the trend but dips? But interpolation at $ t=1,2,3,4 $ with $ d(n)=n^3 $ forces $ d(t)=t^3 $. - AMAZONAWS
Wait—Could the Oceanographer’s Trend Be a Cubic Fit Capable of Dipping? Interpolation at Key Points Suggests $ d(t) = t^3 $
Mar 11, 2026
