Therefore, the only way is if $ d(t) $ is not $ t^3 $, but a different cubic that fits the four points and has a unique minimum. But four points force $ d(t) = t^3 $. - AMAZONAWS
Therefore, the Only Way Is If $ d(t) $ Is Not What We Expect—A Different Cubic with a Unique Minimum—Despite $ d(t) $ Offered as $ t^3 $
Mar 11, 2026
