So $ E(n) = \sum_k=0^n-1 (2k + 1) = n^2 $, since sum of first $ n $ odd numbers is $ n^2 $. - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$So $ E(n) = \sum_{k=0}^{n-1} (2k + 1) = n^2 $, since sum of first $ n $ odd numbers is $ n^2 $.$