So $ d(n) = n^3 $ for $ n = 1,2,3,4 $. Since $ d(t) $ is a cubic polynomial and agrees with $ t^3 $ at four distinct points, by uniqueness of interpolation, - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

So $ d(n) = n^3 $ for $ n = 1,2,3,4 $. Since $ d(t) $ is a cubic polynomial and agrees with $ t^3 $ at four distinct points, by uniqueness of interpolation,