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Home » g(x) = \dfrac53x^3 - 6x^2 + \dfrac433x - 15. - AMAZONAWS

g(x) = \dfrac53x^3 - 6x^2 + \dfrac433x - 15. - AMAZONAWS

📅 March 11, 2026 👤 scraface

Mar 11, 2026

$g(x) = \dfrac{5}{3}x^3 - 6x^2 + \dfrac{43}{3}x - 15.$

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\(\boxed{\left(-\frac{4}{5}, \frac{7}{5}\right)}\)
Thus, the minimum value is \(\boxed{\frac{3}{2}}\).
For $ m = 0 $, $ L = 14 $ (two-digit)
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