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f(2) = 2^3 = 8. - AMAZONAWS
f(2) = 2^3 = 8. - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 Solution: To find the smallest prime factor of 1211, we test divisibility by small primes. First, 1211 is odd, so not divisible by 2. The sum of the digits is $ 1 + 2 + 1 + 1 = 5 $, not divisible by 3. It doesn't end in 0 or 5, so not divisible by 5. Next, test divisibility by 7:
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📌 321_8 = 3 \cdot 8^2 + 2 \cdot 8^1 + 1 \cdot 8^0 = 3 \cdot 64 + 2 \cdot 8 + 1 = 192 + 16 + 1 = 209
