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Home » D'(x) = \frac5016x + 3 = \frac258x + 3 = 0 \Rightarrow x = -\frac2425 - AMAZONAWS

D'(x) = \frac5016x + 3 = \frac258x + 3 = 0 \Rightarrow x = -\frac2425 - AMAZONAWS

📅 March 11, 2026 👤 scraface
Mar 11, 2026
D'(x) = \frac{50}{16}x + 3 = \frac{25}{8}x + 3 = 0 \Rightarrow x = -\frac{24}{25}

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