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\[ a(1)^2 + b(1) + c = 2 \] - AMAZONAWS
\[ a(1)^2 + b(1) + c = 2 \] - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 Wait — unless our initial assumption that $ d(t) = t^3 $ is forced is correct, but it violates the minimum condition. So perhaps $ d(t) $ is not exactly $ t^3 $, but fits it at four points. But a cubic is uniquely determined by four points, so $ d(t) = t^3 $ is the only cubic polynomial satisfying the conditions.
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![\[ a(1)^2 + b(1) + c = 2 \]](https://soloferat.biz.id/images/-a12--b1--c--2-.jpg)
