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Let \(r = \sqrtx^2 + y^2 = c \sin^2\phi\) - AMAZONAWS
Let \(r = \sqrtx^2 + y^2 = c \sin^2\phi\) - AMAZONAWS
📅 March 11, 2026
👤 scraface
Mar 11, 2026
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📌 \frac{9(x - 3)^2}{88} - \frac{16(y - 2)^2}{88} = 1
📌 = \mathbf{i}(2 + 6) - \mathbf{j}(1 - 3) + \mathbf{k}(-2 - 2) = \langle 8, 2, -4 \rangle