Title: Geometry Applications: Composite Figures
Title: Geometry Applications: Composite Figures
[Music]
[Music]
THE PETRONAS TOWERS IN KUALA LUMPUR
ARE THE PRIDE OF MALAYSIA.
THESE GRAND STRUCTURES
ARE THE WORLD'S TALLEST TWIN TOWERS.
THESE 88-FLOOR TOWERS TOOK SEVEN YEARS TO BUILD
AND ARE A TESTAMENT TO MALAYSIA'S ECONOMIC GROWTH
AS WELL AS THE GROWING INFLUENCE
OF THE ASIAN ECONOMY IN THE GLOBAL MARKETPLACE.
THE TWO TOWERS ARE CONNECTED BY
A TWO-LEVEL BRIDGE MIDWAY UP EACH TOWER,
MAKING IT THE HIGHEST TWO LEVEL BRIDGE IN THE WORLD.
PROVIDING A PANORAMIC VIEW OF KUALA LUMPUR,
THE SKYBRIDGE IS ALSO AN EMERGENCY EVACUATION
FROM ONE TOWER TO ANOTHER...
AN ISSUE OF CONCERN IN THE POST-911 WORLD.
MALAYSIA IS A PREDOMINANTLY
MUSLIM COUNTRY AND THIS IS REFLECTED
IN THE ARCHITECTURE OF THE PETRONAS TOWERS.
WHEN VIEWED FROM ABOVE, THE TOWERS REVEAL
A FAMILIAR PATTERN FOUND IN ISLAMIC ART.
NOTE THE OVERLAPPING SQUARES, WHICH IS A COMMON
DESIGN FOUND THROUGHOUT THE ISLAMIC WORLD.
THE CIRCULAR ARCS WERE ADDED TO THE DESIGN
OF THE PETRONAS TOWERS AND WE'LL ANALYZE THESE SHAPES
IN MORE DETAIL LATER.
BUT FOR NOW LET'S FOCUS ON THE OVERLAPPING SQUARES.
AS YOU SAW IN THE PREVIOUS SECTION,
ISLAMIC ARTISANS USED A COMPASS AND STRAIGHTEDGE
TO CREATE ELABORATE PATTERNS THAT WERE PRECISE
BUT COULD ALSO BE REPLICATED QUITE EASILY.
LET'S USE THE TI-NSPIRE TO CONSTRUCT AND EXPLORE THIS
STAR PATTERN MADE UP OF THE TWO OVERLAPPING SQUARES.
TURN ON THE TI-NSPIRE.
CREATE A NEW DOCUMENT.
YOU MAY NEED TO SAVE A PREVIOUS DOCUMENT.
CREATE A GEOMETRY WINDOW AND MAKE SURE
THAT THE VIEW IS THE PLANE GEOMETRY VIEW.
CREATE A HORIZONTAL LINE SEGMENT.
PRESS MENU AND UNDER "POINTS & LINES"
SELECT SEGMENT.
NOW CONSTRUCT A LINE
PERPENDICULAR TO THIS LINE SEGMENT.
PRESS MENU AND UNDER "CONSTRUCTION"
SELECT PERPENDICULAR.
MOVE THE POINTER ABOVE THE HORIZONTAL LINE
AND PRESS ENTER.
CONSTRUCT A CIRCLE WHOSE CENTER IS AT THE POINT
WHERE THE TWO LINES INTERSECT.
PRESS MENU AND UNDER SHAPES SELECT CIRCLE.
AFTER CREATING A CIRCLE, CONSTRUCT TWO MORE CIRCLES
WHOSE CENTERS ARE AT THE POINTS WHERE THE FIRST
CIRCLE AND THE HORIZONTAL LINE SEGMENT INTERSECT.
THESE CIRCLES SHOULD HAVE THE SAME RADIUS AS THE
FIRST CIRCLE AND INTERSECT THAT CIRCLE'S CENTER.
REPEAT THIS PROCESS FOR THE TWO POINTS
WHERE THE VERTICAL LINE INTERSECTS THE FIRST CIRCLE.
IN EACH CASE THE NEW CIRCLE WILL BE CENTERED
AT THE INTERSECTION POINT AND ALSO TOUCH THE CENTER
OF THE FIRST CIRCLE.
YOUR SCREEN SHOULD LOOK LIKE THIS.
MAKE A NOTE OF THESE FOUR HIGHLIGHTED
INTERSECTION POINTS.
USE THE SEGMENT TOOL TO CREATE TWO LINE SEGMENTS
THAT INTERSECT AT THE CENTER OF THE FIRST CIRCLE.
PRESS MENU AND UNDER "POINTS & LINES"
SELECT SEGMENT.
CONNECT THE PAIRS OF POINTS AS SHOWN.
YOU NOW HAVE ALL THE POINTS NECESSARY
TO CONSTRUCT THE OVERLAPPING SQUARES.
LET'S START WITH THE SQUARE
THAT HAS THE HORIZONTAL BASE.
NOTE THESE FOUR HIGHLIGHTED POINTS.
CONTINUING WITH THE SEGMENT TOOL,
CREATE THE SQUARE DEFINED BY THESE FOUR POINTS.
NEXT, USING THESE FOUR HIGHLIGHTED POINTS
CONSTRUCT THE OTHER SQUARE.
THIS SHAPE, AND VARIATIONS OF IT,
ARE FOUND IN MANY ARABESQUES.
THE OUTLINE OF THIS SHAPE IS KNOWN AS A
COMPOSITE FIGURE.
A COMPOSITE FIGURE IS A COMPLEX SHAPE
MADE UP OF SIMPLER GEOMETRIC SHAPES.
IN THE CASE OF THE ISLAMIC STAR THE PRIMARY SHAPES
INCLUDE THE SQUARE WITH THE HORIZONTAL BASE
AND FOUR ISOSCELES TRIANGLES.
THE TOTAL AREA OF THIS COMPOSITE FIGURE
IS THE SUM OF THE AREA OF THE LARGE SQUARE
AND THE COMBINED AREAS OF THE ISOSCELES TRIANGLES.
BUT HOW CAN WE CALCULATE THE AREA OF THE TRIANGLES?
FOR THAT, LET'S LOOK AT A VARIATION
OF THIS COMPOSITE FIGURE.
RATHER THAN LOOKING AT IT AS A COMBINATION
OF ONE SQUARE AND FOUR TRIANGLES,
NOTE THAT THERE IS ALSO A REGULAR HEXAGON.
LOOKED AT THIS WAY,
THE COMPOSITE FIGURE IS ONE HEXAGON
AND SIX CONGRUENT ISOSCELES TRIANGLES.
LET'S LOOK AT THIS TRIANGLE IN MORE DETAIL.
RECALL THAT FOR AN ISOSCELES TRIANGLE,
TWO SIDES AND TWO ANGLES ARE CONGRUENT.
BUT THIS ISOSCELES TRIANGLE IS A CORNER OF A SQUARE
SO THIS IS A SPECIAL TYPE OF ISOSCELES TRIANGLE...
NAMELY AN ISOSCELES RIGHT TRIANGLE.
THIS IS ALSO KNOWN AS THE 45-45-90 DEGREE
RIGHT TRIANGLE.
THESE RIGHT TRIANGLES HAVE SIDE LENGTHS THAT
FORM THE RATIO ONE, ONE, SQUARE ROOT OF TWO.
SUPPOSE THAT THE SIDE LENGTH OF THIS TRIANGLE IS S.
THEN THE LENGTH OF A HYPOTENUSE
IS SQUARE ROOT OF 2S.
THE AREA OF THIS ISOSCELES TRIANGLE IS ONE HALF BASE
TIMES HEIGHT, OR 1/2 S SQUARED.
GOING BACK TO THE COMPOSITE FIGURE, WE CAN SEE
THAT THE LARGE SQUARES HAVE THESE SIDE LENGTHS.
THE TOTAL AREA OF THE COMPOSITE FIGURE
IS THE SUM OF THE SQUARE AND FOUR TIMES THE AREA
OF ONE OF THE ISOSCELES TRIANGLES.
THE SOLUTION IS SHOWN HERE.
ANOTHER WAY TO CALCULATE THE AREA
IS TO USE THE PROPERTIES OF REGULAR POLYGONS.
FOR ANY REGULAR POLYGON THINK OF A CIRCLE
IN WHICH THE POLYGON IS INSCRIBED.
THE INTERIOR ANGLES ARE CONGRUENT AND THE MEASURE
OF EACH ANGLE IS FOUND USING THIS FORMULA
WHERE N IS THE NUMBER OF SIDES OF THE POLYGON.
THERE ARE N ISOSCELES TRIANGLES.
THE BASE OF EACH TRIANGLE IS ONE OF THE EDGES
OF THE POLYGON OF LENGTH S.
THE ALTITUDE OF EACH TRIANGLE, ALSO REFERRED TO
AS THE APATHEM, IS PERPENDICULAR TO SIDE S.
SO THE AREA OF EACH TRIANGLE IS ONE-HALF AS.
SINCE A IS ONE OF THE LEGS OF A RIGHT TRIANGLE,
THEN YOU CAN SOLVE FOR A IN TERMS OF N AND S.
USE THE PYTHAGOREAN THEOREM AND SOLVE FOR A.
WE GET A EQUALS THE SQUARE ROOT OF THE QUANTITY
R SQUARED MINUS S OVER TWO SQUARED
WHERE R IS THE RADIUS OF THE CIRCLE
AND S IS THE LENGTH OF THE POLYGON SIDE.
USING THIS EXPRESSION FOR A IN THE AREA FORMULA
WE GET THIS EQUATION AND THIS EQUATION CAN BE USED
TO FIND THE AREA OF ANY REGULAR POLYGON.
THIS FORMULA COULD BE USED TO FIND THE AREA
OF THE REGULAR HEXAGON SHOWN EARLIER.
THE DESIGN OF THE PETRONAS TOWERS
USES A VARIATION OF THE ISLAMIC SHAPE.
NOTICE THE ADDITIONAL CIRCULAR SECTIONS.
THESE WERE ADDED TO INCREASE THE AMOUNT OF
OFFICE SPACE AVAILABLE, SO THIS FORMS A NEW
COMPOSITE FIGURE SHOWN HERE.
THE QUESTION BECOMES, HOW MUCH MORE AREA HAS BEEN
ADDED TO THE AREA OF THE ORIGINAL COMPOSITE FIGURE?
LET'S ANALYZE THE FIGURES MORE CLOSELY.
A CLOSE UP SHOWS THAT THE CIRCULAR REGION
IS PART OF A CIRCLE WHOSE CENTER IS AT
THE CORNER OF TWO ADJACENT TRIANGLES.
THE RADIUS EXTENDS HALF THE LENGTH OF THE TRIANGLE SIDE.
THIS MEANS THAT THE CIRCLE HAS A RADIUS OF S OVER 2.
THE AREA OF THE FULL CIRCLE IS PI S SQUARED OVER 4.
BUT ONLY A PORTION OF THE CIRCULAR REGION IS USED.
WHAT PORTION? WE KNOW THAT THE INTERIOR ANGLE
OF THE ISOSCELES TRIANGLE IS 45 DEGREES.
THIS MEANS THAT THE CIRCLE
SWEEPS OUT A REGION OF 135 DEGREES.
SINCE A FULL CIRCLE SWEEPS OUT 360 DEGREES,
THE FRACTIONAL AMOUNT THAT THIS PORTION OF THE CIRCLE
SWEEPS OUT IS 135 OVER 360, OR THREE-EIGHTHS.
SO THE AREA OF ONE CIRCULAR SECTION IS THREE-EIGHTHS
OF PI S SQUARED OVER 4, OR THREE PI S SQUARED OVER 32.
AND NOW WE CAN CALCULATE THE TOTAL AREA OF THE
COMPOSITE FIGURE THAT MAKES UP ONE FLOOR IN EACH TOWER.
TAKE THE TOTAL AREA YOU FOUND FOR THE
OVERLAPPING SQUARE SECTION AND ADD IT
TO THE COMBINED AREAS OF THE CIRCULAR SECTIONS.
THE TOTAL AREA IS THIS EXPRESSION.
WHAT PERCENT INCREASE DOES THE ADDITION
OF THE CIRCULAR SECTIONS REPRESENT?
FOR THAT, LET'S USE THE PERCENT INCREASE FORMULA.
DIVIDE THE TOTAL AREA OF THE CIRCULAR SECTIONS
BY THE TOTAL AREA OF THE OVERLAPPING SQUARES.
YOU CAN CREATE A CALCULATOR WINDOW IN THE NSPIRE
TO CALCULATE THE PERCENT INCREASE.
IT TURNS OUT TO BE A ROUGHLY 17% INCREASE IN AREA.
THIS IS A SIZABLE INCREASE IN THE SQUARE FOOTAGE OF
THE AREA, YET THE ADDITION OF THE CIRCULAR SECTIONS
DOES NOT INTERFERE WITH THE OVERALL DESIGN OF THE TOWER.
AND FROM A DISTANCE THESE CIRCULAR SECTIONS
ADD A SMOOTHNESS TO THE LOOK OF THE TOWERS.
COMPOSITE FIGURES PROVIDE A WAY TO CREATE
A VARIETY OF NEW SHAPES WHILE STILL MAINTAINING
THE PROPERTIES OF THE ORIGINAL SHAPES.
AND THE PETRONAS TOWERS PROVIDE A
SOPHISTICATED USE OF SUCH COMPOSITE FIGURES.